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Remove -enable-experimental-nested-generic-types flag #5600

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merged 8 commits into from Nov 18, 2016
Merged

Remove -enable-experimental-nested-generic-types flag #5600

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4e4d281
stdlib: Rework swift_typeName() to use _swift_buildDemanglingForMetad…
slavapestov Nov 18, 2016
a760186
AST: Remove -enable-experimental-nested-generic-types flag
slavapestov Nov 1, 2016
e2be8e2
stdlib: Add swift_getTypeName() tests for nested generics
slavapestov Nov 18, 2016
5564a57
Add changelog entry for nested generic types
slavapestov Nov 2, 2016
9a4c048
stdlib: SetIndex and DictionaryIndex can now be nested types of Set a…
slavapestov Nov 4, 2016
7eaff4a
Update IDE/print_stdlib.swift test
slavapestov Nov 4, 2016
7ba5617
Update api-digester/source-stability.swift test
slavapestov Nov 18, 2016
b3bc749
stdlib: Linux build fix
slavapestov Nov 18, 2016
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Add changelog entry for nested generic types
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@slavapestov
slavapestov committed Nov 18, 2016
commit 5564a57668e86f325e2c005b57bad0e24ee24a66
20 changes: 20 additions & 0 deletions CHANGELOG.md
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Expand Up @@ -20,6 +20,26 @@ CHANGELOG
Swift 3.1
---------

* [SR-1446](https://bugs.swift.org/browse/SR-1446)

Nested types may now appear inside generic types, and nested types may have their own generic parameters:

```swift
struct OuterNonGeneric {
struct InnerGeneric<T> {}
}

struct OuterGeneric<T> {
struct InnerNonGeneric {}

struct InnerGeneric<T> {}
}

extension OuterNonGeneric.InnerGeneric {}
extension OuterGeneric.InnerNonGeneric {}
extension OuterGeneric.InnerGeneric {}
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Can I constrain the outer generic parameter? (if it has a different name)

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Yep

```

* [SR-1009](https://bugs.swift.org/browse/SR-1009):

Constrained extensions allow same-type constraints between generic parameters and concrete types. This enables you to create extensions, for example, on `Array` with `Int` elements:
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